Algebra De Ardura Ejercicios Pdf 12 [UPD]
Algebra De Ardura Ejercicios Pdf 12 [UPD]
Algebra De Ardura Ejercicios Pdf 12
A:
You need to identify the xs..
You are already on the right track, and one of the answers has the following line (from file.txt):
student_id = ctx.reader(file.txt)
This gives you:
def student_id():
student_id = []
with open(‘file.txt’) as file:
for line in file:
student_id.append(line.strip().split(‘:’)[0])
return student_id
This is a good example of using with to make sure that the file closes even if an exception is raised. Notice that the with clause already closes the file.
The code you posted does not make much sense, if you are simply posting a large number of problems. Perhaps you have found a question here that is already answered, and copy-pasted the answer without change.
Q:
How to output the count of occurences in a column of a matrix as a new column?
I have a tab delimited matrix, say a:
[,1] [,2] [,3] [,4]
[1,] 1 1 1 1
[2,] 0 0 1 1
[3,] 1 1 0 0
[4,] 0 0 1 1
[5,] 1 0 1 1
[6,] 1 1 0 1
[7,] 0 0 0 0
I’d like to output a column that outputs the count of the 1’s and the 0’s in the matrix in that order as:
[,1] [,2] [,3] [,4] count
[1,] 1 1 1 1 4
[2,] 0
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